Tolong bantu jawab kak, terimakasih yya
garis pelukis (s) = 13 cm
diameter (d) = 10 cm
jari-jari (r) = 10 cm ÷ 2 = 5 cm
Luas selimut kerucut (Ls) = ... cm²
Ls = π × r × s
Ls = 3,14 × 5 cm × 13 cm
Ls = 3,14 × 65 cm²
Ls = 204,1 cm²
Cari garis pelukis =
→ [tex]\sf \sqrt{ {r}^{2} + {t}^{2} }[/tex]
→ [tex]\sf \sqrt{ {5}^{2} + {13}^{2} }[/tex]
→ [tex]\sf \sqrt{ 25 + 169}[/tex]
→ [tex]\sf \sqrt{194 }[/tex]
→ 13 cm
Luas selimut =
→ π × r × s
→ 3,14 × 5 × 13
→ 15,7 × 13
→ 204,1 cm² (Opsi A)
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